Thursday, July 8, 2010

Need help with an algebra question?

A freighter sailing due north at 12km/h sights a bruiser straight ahead at an unknown distance and speeding due east at unknown speed. After 15 minutes the vessels are 10 km apart, and then, 15 minutes later, they are 13 km apart.(Assume both travel at constant speeds) How far apart are the vessels when the cruiser is due east of the freighter?
Let the distance between the ships when they first sighted the cruiser be x.

Let the distance the cruiser travels after 15 minutes be y



After 15 minutes at 12kph the freighter will travel 12 * (15/60) = 3km.



It

No comments:

Post a Comment

Science & Mathematics