1. Calculate the mass of Na2CO310H2O in grams needed to prepare 200 cm3 of a solution which has a concentration of 0.25 mol dm-3.
2. Calculate the volume in cm3 of dilute sulphuric acid required to react completely with 15 cm3 of sodium hydroxide solution of concentration 3.5 mol dm-3. The concentration of dilute sulphuric acid used for the reaction is 1.5 mol dm-3.
Moles Na2CO310 H2O = 0.200 dm^3 x 0.25 mol/dm^3 = 0.0500
mass Na2CO3*10 H2O= 0.0500 x 286.19 g/mol=14.3 g
moles NaOH = 0.015 dm^3 x 3.5 mol/dm^3 = 0.0525
the balanced equation is
2 NaOH H2SO4 = Na2SO4 2 H2O
moles H2SO4 required = 0.0525/2=0.0263
Volume H2SO4 = 0.0263 mol/ 1.5 mol/dm^3 = 0.0175 dm^3 =
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